Question

2021-08-04

If x is the amount of 10% solution, then \(\displaystyle{150}−{x}\) is the amount of 70% solution.

In terms of percentage, the desired solution must be 54%:

\(\displaystyle{0.10}{x}+{0.70}{\left({150}−{x}\right)}={0.54}{\left({150}\right)}\)

Solve for x:

\(\displaystyle{0.10}{x}+{105}−{0.70}{x}={81}\)

\(\displaystyle−{0.60}{x}+{105}={81}\)

\(\displaystyle−{0.60}{x}=−{24}\)

\(\displaystyle{x}={40}\)

So, the chemist needs 40 milliliters of 10% solution and 110 milliliters of 70% solution.

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